Alligator Crawl with Sled Drag

Feb 08 2012

Tags: ACL, athletic development, collegiate, foam roller, injury, knee, medial, mobility, PCL, Powerlifting, rehab, repair, restoration, sled dragging, stability

Strength Training | admin | 08 February 2012 |

20 Comments

By admin, February 9, 2012 @ 4:23 am
By admin, February 9, 2012 @ 4:23 am

Whats your question?

Omg anonymous you stole my name!
By admin, February 9, 2012 @ 4:23 am

The sled dog drags sleds A and B across the snow. The coefficient of friction between the sleds and the snow is 0.060, the mass of sled A is 100.0 kg, and the mass of sled B is 83.5 kg. If the tension in rope 1 is 137.0 N, what is the tension in rope 2?
By anilbakshi, February 9, 2012 @ 4:23 am

If your case is as under

OO —< .T1 --- T1. > —– oo ==== >> T2 === Dog
A …………………………. B

let common acceleration = a
A sled>
MA * a = T1 – uk* MA* g
B sled>
MB* a = [T2-T1] – uk* MB* g
=============== eliminate unknown (a) by multiplying with MA and MB
MA MB * a = T1*MB – uk* MA*MB* g

MA MB* a = [T2-T1] MA – uk* MA*MB* g
———————————————————————- subtracting
[T2 - T1] MA – T1*MB = 0 ……………………….. uk has no impact

T2 = [MA + MB] T1/MA
T1 = 137 N, MA = 100, MB = 83.5
T2 = tension in rope 2 = 251.395 N
By mordaki, February 9, 2012 @ 4:23 am

I’m looking for a dead weight drag sled. So I can workout my one year old dog. So he is not so hyper because walking four miles a day is not doing it.Thank to anyone who can help.
By sbgruthy1308, February 9, 2012 @ 4:23 am

you could look this up on craigslist.com, they sell a lot of stuff you wouldn’t normally know where to buy.

also, another thing you could try is attaching a harness to a regular sled and then filling it with your own weights or sitting in it yourself.
By wgriffin17, February 9, 2012 @ 4:23 am

A sled is dragged along a horizontal path at a constant speed of 1.5 m/s by a rope that is inclined at an angle of 30.0 respect to the horizontal (the figure below ). The total weight of the sled is 470 N. The tension in the rope is 230 N. How much work is done by the rope on the sled in a time interval of 5 s?
By cushdogjr, February 9, 2012 @ 4:23 am

work = force x distance

So, figure out how far the sled goes in 5 seconds @ 1.5 m/s and plug it in for your distance.

Then, use 230 cos 30 as your force.

Mulitply the two together and you will have your answer.

Good Luck!
By mevturnbull, February 9, 2012 @ 4:23 am

A sled is dragged along a horizontal path at a constant speed of 1.5 m/s by a rope that is inclined at an angle of 30.0° with respect to the horizontal. The total weight of the sled is 470 N. The tension in the rope is 250 N. How much work is done by the rope on the sled in a time interval of 5.0 s?
By gp4rts, February 9, 2012 @ 4:23 am

The energy of the done by the force is T*cos30.0º*s, where s is the distance traveled. At a speed of 1.5 m/s, the distance s in 5.0 s is 7.5 m

W = 250*cos30.0º*7.5 = 1.62*10^3 N
By admin, February 9, 2012 @ 4:23 am

Would this hurt? If you got dragged down a mountain by a team sled and hit your back on a iceberg and then landed in the snow.
By admin, February 9, 2012 @ 4:23 am
By ~Julie~, February 9, 2012 @ 4:23 am

We always take my baby nephew sledding with the dogs. My dog always grabs(with her mouth) the rope on the sled and drags it around with my nephew on it.He is only 2 and weighs 34 lbs. My dog weighs 47 lbs.
Would it be ok for her to pull around my nephew with a sled-dog harness or would it be too much for her?
And do you think she would enjoy it?(I don’t want to force her to drag him around if she doesn’t like it)
Thanks!
By finnigan, February 9, 2012 @ 4:23 am

it sounds like your dog already likes it … getting the right harness would just make it easier for the dog … i don’t think that is wrong, i think the dog likes it and it is fun for all involved … if the dog didn’t want to pull your nephew, he just wouldn’t do it … and of course a video of it posted to youtube would be entertaining too :O)
By black&angel, February 9, 2012 @ 4:23 am

A football coach sits on a sled while two of his players build their strength by dragging the sled across the field with ropes. The friction force on the sled is 1020 and the angle between the two ropes is 25.0. How hard must each player pull to drag the coach at a steady 1.50 ?
By O-360, February 9, 2012 @ 4:23 am

Assume that each player is pulling at 25/2 or 12.5 degrees from the direction of travel of the sled, and assume that the players pull with balanced forces. So, each player must contribute a component in the direction of travel of 1020/2 or 510.

510 = F*Cos(12.5)

F = 510/Cos(12.5) = 522.38
By admin, February 9, 2012 @ 4:23 am
By EricsTowing&AutoSalesInc., February 9, 2012 @ 4:23 am

they use the higher pressure in front of the moving truck as a ram air
to get more cold air into the intake for more power
By z4zorro, February 9, 2012 @ 4:23 am

He does so by pulling with a 25N force on a rope attached to the sled. If the rope is inclined at 20 degrees to the surface of the hill, what is the coefficient of kinetic friction between the sled and snow?

(Kinetic friction force depends on the total normal forces, not just the gravitational force as static friction generally does.)

I’m not a physics person. I’ve been staring at this problem for days. Can someone help explain how this works? Please help!
By BigD, February 9, 2012 @ 4:23 am

I won’t do the entire problem for you, but here is a big hint – draw it all out – BUT draw the slope as a horizontal line with gravity, instead of pulling straight down, is off by 15 degrees away from whichever direction the slope would be.

Normal force points straight up. The rope force is at 20 degrees.

The problem should be much easier now.